Jee Main 2025 — Medium JEE math MCQ
Let $S = N \cup \{0\}$. Define a relation $R$ from $S$ to $R$ by $R = \{ (x, y) : \log_e y = x \log_e \left( \frac{2}{3} \right), x \in S, y \in R \}$ Then, the sum of all the elements in the range of $R$ is equal to
- A. $\frac{10}{9}$
- B. $\frac{5}{2}$
- C. $\frac{\sqrt{3}}{2}$
- D. $\frac{1}{3}$
Solution
The correct option is **D**. (D. $\frac{1}{3}$)
