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Jee Main 2025Medium JEE math MCQ

Let $\alpha, \beta (\alpha \neq \beta)$ be the values of $m$, for which the equations $x + y + z = 1, x + 2y + 4z = m$ and $x + 4y + 10z = m^2$ have infinitely many solutions. Then the value of $\sum_{n=1}^{10} (n^\alpha + n^\beta)$ is equal to
  1. A. 3080
  2. B. 560
  3. C. 3410
  4. D. 440

Solution

The correct option is **D**. (D. 440)

MATH

mediumPYQ Reworded
Question
Read carefully, then pick the best option.
Let α,β(αβ)\alpha, \beta (\alpha \neq \beta) be the values of mm, for which the equations x+y+z=1,x+2y+4z=mx + y + z = 1, x + 2y + 4z = m and x+4y+10z=m2x + 4y + 10z = m^2 have infinitely many solutions. Then the value of n=110(nα+nβ)\sum_{n=1}^{10} (n^\alpha + n^\beta) is equal to
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