Jee Main 2025 — Medium JEE math MCQ
Let $\alpha, \beta (\alpha \neq \beta)$ be the values of $m$, for which the equations $x + y + z = 1, x + 2y + 4z = m$ and $x + 4y + 10z = m^2$ have infinitely many solutions. Then the value of $\sum_{n=1}^{10} (n^\alpha + n^\beta)$ is equal to
- A. 3080
- B. 560
- C. 3410
- D. 440
Solution
The correct option is **D**. (D. 440)
