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Jee Main 2025Medium JEE math MCQ

If \( \alpha x + \beta y = 109 \) is the equation of the chord of the ellipse \( \frac{x^2}{\alpha} + \frac{y^2}{\beta} = 1 \), whose mid point is \( \left( \frac{1}{2}, \frac{1}{4} \right) \), then \( \alpha + \beta \) is equal to
  1. A. 58
  2. B. 46
  3. C. 37
  4. D. 72

Solution

The correct option is **A**. (A. 58)

MATH

mediumPYQ Reworded
Question
Read carefully, then pick the best option.
If αx+βy=109 \alpha x + \beta y = 109 is the equation of the chord of the ellipse x2α+y2β=1 \frac{x^2}{\alpha} + \frac{y^2}{\beta} = 1 , whose mid point is (12,14) \left( \frac{1}{2}, \frac{1}{4} \right) , then α+β \alpha + \beta is equal to
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Jee Main 2025 — Medium JEE Mathematics MCQ | MyGoalPrep