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Jee Main 2025 — Medium JEE math MCQ

If $\alpha + i\beta$ and $\gamma + i\delta$ are the roots of $x^2 - (3 - 2i)x - (2i - 2) = 0$, $i = \sqrt{-1}$, then $\alpha\gamma + \beta\delta$ is equal to
  1. A. $-2$
  2. B. $6$
  3. C. $-6$
  4. D. $2$

Solution

The correct option is **D**. (D. $2$)

MATH

medium • PYQ Reworded
Question
Read carefully, then pick the best option.
If α+iβ\alpha + i\beta and γ+iδ\gamma + i\delta are the roots of x2−(3−2i)x−(2i−2)=0x^2 - (3 - 2i)x - (2i - 2) = 0, i=−1i = \sqrt{-1}, then αγ+βδ\alpha\gamma + \beta\delta is equal to
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Jee Main 2025 — Medium JEE Mathematics MCQ | MyGoalPrep