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Jee Main 2025Medium JEE math MCQ

Let $f : \mathbb{R} \setminus \{0\} \to (-\infty, 1)$ be a polynomial of degree 2, satisfying $f(x) f\left( \frac{1}{x} \right) = f(x) + f\left( \frac{1}{x} \right)$. If $f(K) = -2K$, then the sum of squares of all possible values of $K$ is
  1. A. 7
  2. B. 6
  3. C. 1
  4. D. 9

Solution

The correct option is **B**. (B. 6)

MATH

mediumPYQ Reworded
Question
Read carefully, then pick the best option.
Let f:R{0}(,1)f : \mathbb{R} \setminus \{0\} \to (-\infty, 1) be a polynomial of degree 2, satisfying f(x)f(1x)=f(x)+f(1x)f(x) f\left( \frac{1}{x} \right) = f(x) + f\left( \frac{1}{x} \right). If f(K)=2Kf(K) = -2K, then the sum of squares of all possible values of KK is
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Jee Main 2025 — Medium JEE Mathematics MCQ | MyGoalPrep