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Jee Main 2025 — Medium JEE math MCQ

If \(\int \frac{9x^2 \cos \pi x}{(1 + x^2)^2} dx = \pi (\alpha x^2 + \beta), \alpha, \beta \in \mathbb{Z}\), then \((\alpha + \beta)^2\) equals \[
  1. A. \ 64 \quad
  2. B. \ 196 \quad
  3. C. \ 144 \quad
  4. D. \ 100. \]

Solution

The correct option is **D**. (D. \ 100. \])

MATH

medium • PYQ Reworded
Question
Read carefully, then pick the best option.
If ∫9x2cos⁡πx(1+x2)2dx=π(αx2+β),α,β∈Z\int \frac{9x^2 \cos \pi x}{(1 + x^2)^2} dx = \pi (\alpha x^2 + \beta), \alpha, \beta \in \mathbb{Z}, then (α+β)2(\alpha + \beta)^2 equals \[
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Jee Main 2025 — Medium JEE Mathematics MCQ | MyGoalPrep