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Jee Main 2025Medium JEE math MCQ

If \( f(x) = \frac{x^2}{2x^2 + \sqrt{2}}, x \in \mathbb{R}, \) then \( \sum_{k=1}^{81} f \left( \frac{k}{82} \right) \) is equal to
  1. A. \( 1.81\sqrt{2} \)
  2. B. \( 41 \)
  3. C. \( 82 \)
  4. D. \( \frac{81}{2} \)

Solution

The correct option is **D**. (D. \( \frac{81}{2} \))

MATH

mediumPYQ Reworded
Question
Read carefully, then pick the best option.
If f(x)=x22x2+2,xR, f(x) = \frac{x^2}{2x^2 + \sqrt{2}}, x \in \mathbb{R}, then k=181f(k82) \sum_{k=1}^{81} f \left( \frac{k}{82} \right) is equal to
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Jee Main 2025 — Medium JEE Mathematics MCQ | MyGoalPrep