Jee Main 2025 — Medium JEE math MCQ
If \( f(x) = \frac{x^2}{2x^2 + \sqrt{2}}, x \in \mathbb{R}, \) then \( \sum_{k=1}^{81} f \left( \frac{k}{82} \right) \) is equal to
- A. \( 1.81\sqrt{2} \)
- B. \( 41 \)
- C. \( 82 \)
- D. \( \frac{81}{2} \)
Solution
The correct option is **D**. (D. \( \frac{81}{2} \))
