Jee Main 2025 — Medium JEE math MCQ
If $7 = 5 \times 1 + \frac{1}{7} (5 + \alpha) + \frac{1}{7^2} (5 + 2\alpha) + \frac{1}{7^3} (5 + 3\alpha) + \cdots \infty$, then the value of $\alpha$ is
- A. $\frac{6}{7}$
- B. 6
- C. $\frac{1}{7}$
- D. 1
Solution
The correct option is **B**. (B. 6)
