MyGoalPrep LogoMyGoalPrep.com

Jee Main 2025 — Medium JEE math MCQ

The equation of the chord, of the ellipse $\frac{x^2}{25} + \frac{y^2}{16} = 1$, whose mid-point is $(3, 1)$, is: $25x + 101y = 176$
  1. A. $48x + 25y = 169$
  2. B. $5x + 16y = 31$
  3. C. $4x + 122y = 134$
  4. D. $4x + 122y = 134$

Solution

The correct option is **A**. (A. $48x + 25y = 169$)

MATH

medium • PYQ Reworded
Question
Read carefully, then pick the best option.
The equation of the chord, of the ellipse x225+y216=1\frac{x^2}{25} + \frac{y^2}{16} = 1, whose mid-point is (3,1)(3, 1), is: 25x+101y=17625x + 101y = 176
AI hints
Ask for a nudge. Keep it specific.
Jee Main 2025 — Medium JEE Mathematics MCQ | MyGoalPrep