Jee Main 2025 — Medium JEE math MCQ
\(A\) and \(B\) alternately throw a pair of dice. \(A\) wins if he throws a sum of 5 before \(B\) throws a sum of 8, and \(B\) wins if he throws a sum of 8 before \(A\) throws a sum of 5. The probability, that \(A\) wins if \(A\) makes the first throw, is
- A. \(\frac{9}{17}\)
- B. \(\frac{9}{17}\)
- C. \(\frac{9}{17}\)
- D. \(\frac{8}{17}\)
Solution
The correct option is **B**. (B. \(\frac{9}{17}\))