Jee Main 2025 — Medium JEE math MCQ
Let the lines $3x - 4y - \alpha = 0$, $8x - 11y - 33 = 0$, and $2x - 3y + \lambda = 0$ be concurrent. If the image of the point $(1, 2)$ in the line $2x - 3y + \lambda = 0$ is $\left(\frac{57}{13}, \frac{-40}{13}\right)$, then $|\alpha\lambda|$ is equal to
- A. $84$
- B. $113$
- C. $91$
- D. $101$
Solution
The correct option is **C**. (C. $91$)
