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Jee Main 2025 — Medium JEE math MCQ

\( \lim_{x \to \infty} \frac{(2x^2-3x+5)(3x-1)^{\frac{2}{3}}}{(3x^2+5x+4)\sqrt{(3x+2)^3}} \) is equal to
  1. A. \( \frac{2}{3} \sqrt{e} \)
  2. B. \( \frac{3e}{5} \)
  3. C. \( \frac{2e}{3} \)
  4. D. \( \frac{3e}{5} \)

Solution

The correct option is **C**. (C. \( \frac{2e}{3} \))

MATH

medium • PYQ Reworded
Question
Read carefully, then pick the best option.
lim⁡x→∞(2x2−3x+5)(3x−1)23(3x2+5x+4)(3x+2)3 \lim_{x \to \infty} \frac{(2x^2-3x+5)(3x-1)^{\frac{2}{3}}}{(3x^2+5x+4)\sqrt{(3x+2)^3}} is equal to
AI hints
Ask for a nudge. Keep it specific.