Jee Main 2025 — Medium JEE math MCQ
If \( \frac{\pi}{6} \leq x \leq \frac{3\pi}{4} \), then \( \cos^{-1}\left(\frac{12}{13}\cos x + \frac{5}{13}\sin x\right) \) is equal to
- A. \( x - \tan^{-1}\frac{4}{3} \) -
- B. \( x + \tan^{-1}\frac{4}{5} \) -
- C. \( x - \tan^{-1}\frac{5}{12} \) -
- D. \( x + \tan^{-1}\frac{5}{12} \)
Solution
The correct option is **C**. (C. \( x - \tan^{-1}\frac{5}{12} \) -)
