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Jee Main 2025Medium JEE math MCQ

Let the curve \( z(1 + i) + \bar{z}(1 - i) = 4 \), \( z \in \mathbb{C} \), divide the region \( |z - 3| \leq 1 \) into two parts of areas \( \alpha \) and \( \beta \). Then \( |\alpha - \beta| \) equals
  1. A. \( 1 + \frac{\pi}{2} \)
  2. B. \( 1 + \frac{\pi}{3} \)
  3. C. \( 1 + \frac{\pi}{6} \)
  4. D. \( 1 + \frac{\pi}{4} \)

Solution

The correct option is **A**. (A. \( 1 + \frac{\pi}{2} \))

MATH

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Question
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Let the curve z(1+i)+zˉ(1i)=4 z(1 + i) + \bar{z}(1 - i) = 4 , zC z \in \mathbb{C} , divide the region z31 |z - 3| \leq 1 into two parts of areas α \alpha and β \beta . Then αβ |\alpha - \beta| equals
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Jee Main 2025 — Medium JEE Mathematics MCQ | MyGoalPrep