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Jee Main 2025 — Medium JEE math MCQ

The area of the region, inside the circle \((x - 2\sqrt{3})^2 + y^2 = 12\) and outside the parabola \(y^2 = 2\sqrt{3}x\) is
  1. A. \(3\pi + 8\)
  2. B. \(6\pi - 16\)
  3. C. \(3\pi - 8\)
  4. D. \(6\pi - 8\)

Solution

The correct option is **B**. (B. \(6\pi - 16\))

MATH

medium • PYQ Reworded
Question
Read carefully, then pick the best option.
The area of the region, inside the circle (x−23)2+y2=12(x - 2\sqrt{3})^2 + y^2 = 12 and outside the parabola y2=23xy^2 = 2\sqrt{3}x is
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