Jee Main 2025 — Medium JEE math MCQ
Let $L_1 : \frac{x-1}{2} = \frac{y-2}{3} = \frac{z-3}{4}$ and $L_2 : \frac{x-3}{2} = \frac{y-4}{3} = \frac{z-5}{4}$ be two lines. Then which of the following points lies on the line of the shortest distance between $L_1$ and $L_2$?
- A. $\left( \frac{14}{5}, -3, \frac{22}{3} \right)$
- B. $\left( -\frac{5}{3}, -7, 1 \right)$
- C. $\left( 2, 3, \frac{1}{2} \right)$
- D. $\left( \frac{5}{3}, -1, \frac{1}{2} \right)$
Solution
The correct option is **A**. (A. $\left( \frac{14}{5}, -3, \frac{22}{3} \right)$)
