Jee Main 2025 — Medium JEE math MCQ
Let for $f(x) = 7 \tan^8 x + 7 \tan^6 x - 3 \tan^4 x - 3 \tan^2 x$, $I_1 = \int_{0}^{\pi/4} f(x) \, dx$ and $I_2 = \int_{0}^{\pi/4} x f(x) \, dx$. Then $7I_1 + 12I_2$ is equal to
- A. 2
- B. 1
- C. $2\pi$
- D. $\pi$
Solution
The correct option is **B**. (B. 1)